You asked: How many ways can 7 beads be placed on a bracelet with no clasp?

How many ways can nine beads be placed on a bracelet with no clasp?

This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

How many ways can 8 persons be seated at a round table?

ways, where n refers to the number of elements to be arranged. = 5040 ways.

How many ways can letters be arranged?

Now, the formula of expanding factorial is n! =n×(n−1)×(n−2)×…… ×3×2×1. Therefore, we can arrange the letters in the word ‘FACTOR’ in 720 ways.

How many ways can 7 beads can be arranged to form a necklace?

2520. 5040.

How many ways can 3 people sit in a round table?

So there are two answers: There are 3! = 6 different ways of placing these three people in three distinct chairs. However, it we decide to consider rotated arrangements as basically the same, then there are only 2 ways.

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How many necklaces can you make with 6 beads of 3 colors?

The first step is easy: the number of ways to colour 6 beads, where each bead can be red, green or blue, is 36 = 729. Next we put the beads on a necklace, and account for duplicate patterns.

How many ways can you arrange things in a circle?

Coming back to the question – In how many ways can 5 distinct objects be arranged in a circle? Now there are 5! or 120 different linear arrangements possible.

How many ways can 12 beads be arranged on a bracket?

12 different beads can be arranged among themselves in a circular order in (12-1)!= 11! Ways. Now, in the case of necklace, there is not distinction between clockwise and anti-clockwise arrangements.

How many ways can eight beads no two of which are the same be arranged on a chain with a clasp?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

How many bracelets can be made by stringing 9 different colored beads together?

by stringing together 9 different coloured beads one can make 9! (9 factorial ) bracelet. 9! = 9×8×7×6×5×4×3×2×1 = 362880 ways.