**Contents**show

## How many necklaces can be formed with a different Coloured beads?

2520 Ways **8** beads of different colours be strung as a necklace if can be wear from both side.

## How many necklaces can you make with 10 beads of colors?

This is easy: count all permutations of 10 beads, 10!, then divide by 20 because we counted each permutation 10 times due to rotation, and counted each of these twice because you can flip the necklace over. Thus the answer is 10!/20 = **181440**.

## How many different necklaces can be formed using 9 different Coloured beads?

This leaves us with 18,150 – 6 = 18,144 strings. The total number of necklaces we can form with these strings is 18,144 ÷ 9 = **2016**.

## What are the number of ways in which 10 beads can be arranged to form a necklace?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = **181440**.

## How many necklace of 12 beads each can be made from 18 beads of different Colours?

Correct Option: C

First, we can select 12 beads out of 18 beads in ^{18}C_{12} ways. Now, these 12 beads can make a necklace in **11! / 2 ways** as clockwise and anti-clockwise arrangements are same. So, required number of ways = [ ^{18}C_{12} . 11! ] / 2!

## How many ways can 12 beads be arranged on a bracket?

12 different beads can be arranged among themselves in a circular order in **(12-1)!=** **11!** **Ways**. Now, in the case of necklace, there is not distinction between clockwise and anti-clockwise arrangements.

## How many necklaces can be formed with 6 white and 5 red beads if each necklace is unique how many can be formed?

5! but correct answer is **21**.

## How many ways can 6 beads be arranged in a string?

6P6 = **720** or 6!

## How many different bangles can be formed from 8 different colored beads?

How many different bangles can be formed from 8 different colored beads? Answer: **5,040 bangles** .

## How many ways can you make a bracelet with 5 different beads?

Thus for n=5, there are possible **4**!/2=12 different bracelets.